What is the IP address and TCP harbor number used by the client computer (source) the is delivering the document to gaia.cs.umass.edu?Client IP : 192.168.1.102 TCP port: health-polling (1161)2. What is the IP resolve of gaia.cs.umass.edu? ~ above what harbor number is that sending and receiving TCP segments because that this connection?Ip address : 220.127.116.11 TCP Port: 80
3. What is the IP resolve and TCP harbor number offered by your client computer (source) to transport the file to gaia.cs.umass.edu? 192.168.2.3 resource port:(1742)4. What is the sequence variety of the TCP SYN segment the is supplied to begin the TCP connection between the customer computer and also gaia.cs.umass.edu? What is it in the segment that identifies the segment together a SYN segment?Sequence number: 0 (relative succession number)The syn segement have the right to be checked out to be collection to 1 (.... .... ..1. = Syn: Set) This mirrors it is a syn segment5. What is the sequence variety of the SYNACK segment sent by gaia.cs.umass.edu to the client computer in reply to the SYN? What is the value of the ACKnowledgement field in the SYNACK segment? how did gaia.cs.umass.edu recognize that value? What is it in the segment that identifies the segment together a SYNACK segment?The sequence number: Acknowledgement number: 1 (relative ack number)value of the ACKnowledgement field is 1gaia.cs.umass.edu determined that value by including 1 come the sequence variety of the previous segement.This segment is figured out as a synack segment acknowledgement and also syn bits room both set.
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6. What is the sequence variety of the TCP segment containing the HTTP article command? keep in mind that in order to find the write-up command, you’ll need to dig into the packet content ar at the bottom of the Wireshark window, in search of a segment with a “POST” within its DATA field.The sequence number of the TCP segment containing the HTTP post Command is 1
7. Consider the TCP segment containing the HTTP write-up as the very first segment in the TCP connection. What room the sequence number of the very first six segment in the TCP link (including the segment include the HTTP POST)? in ~ what time to be each segment sent? once was the ACK because that each segment received? given the difference in between when every TCP segment was sent, and when the acknowledgement to be received, what is the RTT value for every of the 6 segments? What is the EstimatedRTT worth (see page 249 in text) after ~ the receipt of every ACK? Assume that the value of the EstimatedRTT is same to the measure up RTT for the an initial segment, and also then is computed making use of the EstimatedRTT equation on web page 249 for all succeeding segments. Note: Wireshark has a nice attribute that allows you to plot the RTT because that each that the TCP segment sent. Pick a TCP segment in the “listing of captured packets” window that is being sent from the customer to the gaia.cs.umass.edu server. Then select: Statistics->TCP present Graph->Round pilgrimage Time Graph.
|segment||Relative Segment number||Segment number||Time sent||Acknowledgement Received||RTT||Estimated RTT|
Estimated RTT packet 1 : 0.875 * .028 + 0.125 * .028= .028Estimated RTT packet 2 : 0.875 * .042+ 0.125 * .035 = .035Estimated RTT packet 3 : 0.875 * .054 + 0.125 * .070 = .070Estimated RTT packet 4 : 0.875 * .055+ 0.125 * .114 = .114Estimated RTT packet 5 : 0.875 * .077+ 0.125 * .140 = .140Estimated RTT packet 6 : 0.875 * .078+ 0.125 * .190 = .1908. What is the size of every of the an initial six TCP segments?Segment 1 = 565 bytesSegment 2 = 1460 bytesSegment 3 = 1460 bytesSegment 4 = 1460 bytesSegment 5 = 1460 bytesSegment 6 = 1460 bytes9. What is the minimum quantity of available buffer room advertised at the got for the entire trace? walk the lack of recipient buffer room ever throttle the senderThe minimum amount of obtainable buffer room is advertised as (Calculated window size): 5840 bytes. The absence of recipient buffer room does not ever throttle the sender.10. Room there any type of retransmitted segment in the trace file? What did you check for (in the trace) in order come answer this question?There room no retransmitted segments. To check this, ns looked for any type of repeating segment numbers.11. How much data go the receiver commonly acknowledge in one ACK? can you identify cases where the receiver is ACKing every other received segment (see Table 3.2 on web page 257 in the text).The receiver typically acknowledges 1460 bytes in an ack. If the data is doubled then that segement is acking every other12. What is the throughput (bytes transferred per unit time) because that the TCP connection? describe how friend calculated this value.The file is 177851 bytes dive the by the full time 7.596 seconds and also average throughput is 23413.77 bytes every second
13. Usage the Time-Sequence-Graph(Stevens) plotting device to see the sequence number versus time plot of segment being sent out from the customer to the gaia.cs.umass.edu server.
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Have the right to you determine where TCP’s slowstart phase begins and also ends, and also where congestion avoidance take away over? discuss ways in which the measured data different from the idealized habits of TCP the we’ve studied in the textThe slowstart phase begins at about zero and also ends at about .15 secs in according to the graph then congestion takes over. The measure data is only using a portion of the window size rather of the idealized 1/3 to a half.